WebFeb 19, 2010 · In the figure, r1 = 5 and r2 = 7 cm. Before the conducting spheres are connected by the wire a charge of 5×10-7 C is placed on the smaller sphere while the larger sphere is uncharged. Calculate the charge on the smaller sphere after the wire is connected. Assume that the separation of the spheres is very large compared to their radii. WebThe radii of two spheres are 4ft and 8ft find the volume of a spheres whose surface area is equal to the sum of the surface areas of these two spheres. 1 answer; Math; asked by Perlie; 1,314 views; Given the arrangement of charged particles in the figure below, find the net electrostatic force on the q2 = 12.33-µC charged particle.
Two conducting spheres of radii 3 cm and 1 cm are separated
WebIf the centres of the spheres are a distance d apart the force between the spheres is: F = kq₁q₂/d². = k (V₁r₁/k) (V₂r₂/k)/d². = V₁r₁V₂r₂/ (kd²) Since V₁ = V₂ (=V) this becomes: F = V²r₁r₂/ … http://www.phys.ufl.edu/courses/phy2049/summer_exams/2049-sum12/Exam1SolSM12.pdf gps tracker for cat
Two metallic spheres of radii 1cm and 3cm are given charges of
WebIf the centres of the spheres are a distance d apart the force between the spheres is: F = kq₁q₂/d². = k (V₁r₁/k) (V₂r₂/k)/d². = V₁r₁V₂r₂/ (kd²) Since V₁ = V₂ (=V) this becomes: F = V²r₁r₂/ (kd²) Just stick the values in (remember distances must be converted to metres). WebOct 13, 2024 · Electric potential due to two spheres. The two conducting spheres, of radii r 1 and r 2 have charges Q 1 and Q 2. The distance between their centers is AB. BC is perpendicular to AB. The problem asks to determine the potential at the mid-point of the line BC, point P (not shown). My approach was to determine the distance AP. WebCharge flow from high potential to low potential. If these metallic spheres are connected by a conducting wire final potential of the spheres will be equal. Let are the final charges on the spheres, Final Answer. The final charge on the bigger sphere is 3×10 -2. C gps tracker for car without subscription